Base | Representation |
---|---|
bin | 11010001101001001110001… |
… | …010111101110111000101111 |
3 | 120010002002021112021210112022 |
4 | 122031021301113232320233 |
5 | 110101301223420431011 |
6 | 1045042304451500355 |
7 | 33163521063000143 |
oct | 3215116127567057 |
9 | 503062245253468 |
10 | 115253054467631 |
11 | 337a5600673713 |
12 | 10b149928b76bb |
13 | 4c404161998b2 |
14 | 20663c5a3d223 |
15 | d4cee2ea08db |
hex | 68d2715eee2f |
115253054467631 has 2 divisors, whose sum is σ = 115253054467632. Its totient is φ = 115253054467630.
The previous prime is 115253054467601. The next prime is 115253054467633. The reversal of 115253054467631 is 136764450352511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 115253054467631 - 222 = 115253050273327 is a prime.
It is a super-2 number, since 2×1152530544676312 (a number of 29 digits) contains 22 as substring.
Together with 115253054467633, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115253054467633) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57626527233815 + 57626527233816.
It is an arithmetic number, because the mean of its divisors is an integer number (57626527233816).
Almost surely, 2115253054467631 is an apocalyptic number.
115253054467631 is a deficient number, since it is larger than the sum of its proper divisors (1).
115253054467631 is an equidigital number, since it uses as much as digits as its factorization.
115253054467631 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9072000, while the sum is 53.
The spelling of 115253054467631 in words is "one hundred fifteen trillion, two hundred fifty-three billion, fifty-four million, four hundred sixty-seven thousand, six hundred thirty-one".
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