115374373 has 2 divisors, whose sum is σ = 115374374. Its totient is φ = 115374372.

The previous prime is 115374367. The next prime is 115374379. The reversal of 115374373 is 373473511.

It is a balanced prime because it is at equal distance from previous prime (115374367) and next prime (115374379).

It can be written as a sum of positive squares in only one way, i.e., 115283169 + 91204 = 10737^2 + 302^2 .

It is an emirp because it is prime and its reverse (373473511) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-115374373 is a prime.

It is a super-2 number, since 2×115374373² = 26622491890286258, which contains 22 as substring.

It is equal to p_6592813 and since 115374373 and 6592813 have the same sum of digits, it is a Honaker prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115374379) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57687186 + 57687187.

It is an arithmetic number, because the mean of its divisors is an integer number (57687187).

Almost surely, 2^115374373 is an apocalyptic number.

It is an amenable number.

115374373 is a deficient number, since it is larger than the sum of its proper divisors (1).

115374373 is an equidigital number, since it uses as much as digits as its factorization.

115374373 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 26460, while the sum is 34.

The square root of 115374373 is about 10741.2463429529. The cubic root of 115374373 is about 486.8215386146.

The spelling of 115374373 in words is "one hundred fifteen million, three hundred seventy-four thousand, three hundred seventy-three".