Base | Representation |
---|---|
bin | 10101100001000001… |
… | …11000001000001101 |
3 | 1002211000220000210212 |
4 | 22300200320020031 |
5 | 142124120434432 |
6 | 5150121212205 |
7 | 556152540116 |
oct | 126040701015 |
9 | 32730800725 |
10 | 11551343117 |
11 | 4998483066 |
12 | 22a4631065 |
13 | 1121218292 |
14 | 7b81cd20d |
15 | 47919a2b2 |
hex | 2b083820d |
11551343117 has 2 divisors, whose sum is σ = 11551343118. Its totient is φ = 11551343116.
The previous prime is 11551343093. The next prime is 11551343119. The reversal of 11551343117 is 71134315511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9724720996 + 1826622121 = 98614^2 + 42739^2 .
It is a cyclic number.
It is not a de Polignac number, because 11551343117 - 26 = 11551343053 is a prime.
Together with 11551343119, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11551343119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5775671558 + 5775671559.
It is an arithmetic number, because the mean of its divisors is an integer number (5775671559).
Almost surely, 211551343117 is an apocalyptic number.
It is an amenable number.
11551343117 is a deficient number, since it is larger than the sum of its proper divisors (1).
11551343117 is an equidigital number, since it uses as much as digits as its factorization.
11551343117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6300, while the sum is 32.
Adding to 11551343117 its reverse (71134315511), we get a palindrome (82685658628).
The spelling of 11551343117 in words is "eleven billion, five hundred fifty-one million, three hundred forty-three thousand, one hundred seventeen".
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