Base | Representation |
---|---|
bin | 10101100001011110… |
… | …10001010000010010 |
3 | 1002211021222201022010 |
4 | 22300233101100102 |
5 | 142131102203200 |
6 | 5150334123350 |
7 | 556226602662 |
oct | 126057212022 |
9 | 32737881263 |
10 | 11555116050 |
11 | 499a61a795 |
12 | 22a5950556 |
13 | 1121c3969a |
14 | 7b88d21a2 |
15 | 479693150 |
hex | 2b0bd1412 |
11555116050 has 48 divisors (see below), whose sum is σ = 29902639680. Its totient is φ = 2947391040.
The previous prime is 11555116043. The next prime is 11555116063. The reversal of 11555116050 is 5061155511.
It is a super-3 number, since 3×115551160503 (a number of 31 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a junction number, because it is equal to n+sod(n) for n = 11555115999 and 11555116017.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1671205 + ... + 1678104.
It is an arithmetic number, because the mean of its divisors is an integer number (622971660).
Almost surely, 211555116050 is an apocalyptic number.
11555116050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11555116050 is an abundant number, since it is smaller than the sum of its proper divisors (18347523630).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11555116050 is a wasteful number, since it uses less digits than its factorization.
11555116050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3349347 (or 3349342 counting only the distinct ones).
The product of its (nonzero) digits is 3750, while the sum is 30.
The spelling of 11555116050 in words is "eleven billion, five hundred fifty-five million, one hundred sixteen thousand, fifty".
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