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115632316101557 is a prime number
BaseRepresentation
bin11010010010101010111111…
…001000000011001110110101
3120011102100012220222000102202
4122102222333020003032311
5110124004440410222212
61045532430324514245
733233105405461403
oct3222527710031665
9504370186860382
10115632316101557
1133931431a026a2
1210b7639884b985
134c6a108179cb8
14207a8c3836473
15d57cdddcd0c2
hex692abf2033b5

115632316101557 has 2 divisors, whose sum is σ = 115632316101558. Its totient is φ = 115632316101556.

The previous prime is 115632316101553. The next prime is 115632316101559. The reversal of 115632316101557 is 755101613236511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 114094143168196 + 1538172933361 = 10681486^2 + 1240231^2 .

It is a cyclic number.

It is not a de Polignac number, because 115632316101557 - 22 = 115632316101553 is a prime.

Together with 115632316101559, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115632316101553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57816158050778 + 57816158050779.

It is an arithmetic number, because the mean of its divisors is an integer number (57816158050779).

Almost surely, 2115632316101557 is an apocalyptic number.

It is an amenable number.

115632316101557 is a deficient number, since it is larger than the sum of its proper divisors (1).

115632316101557 is an equidigital number, since it uses as much as digits as its factorization.

115632316101557 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 567000, while the sum is 47.

The spelling of 115632316101557 in words is "one hundred fifteen trillion, six hundred thirty-two billion, three hundred sixteen million, one hundred one thousand, five hundred fifty-seven".