Base | Representation |
---|---|
bin | 1010100011100111101110… |
… | …0111011100100101111101 |
3 | 1112002121220001110001000022 |
4 | 2220321323213130211331 |
5 | 3010132242321301333 |
6 | 40404114503541525 |
7 | 2305404103332401 |
oct | 250717347344575 |
9 | 45077801401008 |
10 | 11607075572093 |
11 | 3775595623551 |
12 | 137564215a8a5 |
13 | 662708c272c1 |
14 | 2c1add409101 |
15 | 151dd77bcc98 |
hex | a8e7b9dc97d |
11607075572093 has 2 divisors, whose sum is σ = 11607075572094. Its totient is φ = 11607075572092.
The previous prime is 11607075572069. The next prime is 11607075572153. The reversal of 11607075572093 is 39027557070611.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11046137486329 + 560938085764 = 3323573^2 + 748958^2 .
It is a cyclic number.
It is not a de Polignac number, because 11607075572093 - 28 = 11607075571837 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11607075572063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5803537786046 + 5803537786047.
It is an arithmetic number, because the mean of its divisors is an integer number (5803537786047).
Almost surely, 211607075572093 is an apocalyptic number.
It is an amenable number.
11607075572093 is a deficient number, since it is larger than the sum of its proper divisors (1).
11607075572093 is an equidigital number, since it uses as much as digits as its factorization.
11607075572093 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2778300, while the sum is 53.
The spelling of 11607075572093 in words is "eleven trillion, six hundred seven billion, seventy-five million, five hundred seventy-two thousand, ninety-three".
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