Base | Representation |
---|---|
bin | 1010100111111101001010… |
… | …1011111010001000111111 |
3 | 1112100202010100201210021222 |
4 | 2221333102223322020333 |
5 | 3012342304001203034 |
6 | 40502232542343555 |
7 | 2313651501343112 |
oct | 251772253721077 |
9 | 45322110653258 |
10 | 11681550803519 |
11 | 37a4132989193 |
12 | 1387b6788abbb |
13 | 66974758568c |
14 | 2c5566520579 |
15 | 153ce5c2812e |
hex | a9fd2afa23f |
11681550803519 has 2 divisors, whose sum is σ = 11681550803520. Its totient is φ = 11681550803518.
The previous prime is 11681550803513. The next prime is 11681550803521. The reversal of 11681550803519 is 91530805518611.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11681550803519 is a prime.
It is a super-2 number, since 2×116815508035192 (a number of 27 digits) contains 22 as substring.
Together with 11681550803521, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11681550803513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5840775401759 + 5840775401760.
It is an arithmetic number, because the mean of its divisors is an integer number (5840775401760).
Almost surely, 211681550803519 is an apocalyptic number.
11681550803519 is a deficient number, since it is larger than the sum of its proper divisors (1).
11681550803519 is an equidigital number, since it uses as much as digits as its factorization.
11681550803519 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296000, while the sum is 53.
The spelling of 11681550803519 in words is "eleven trillion, six hundred eighty-one billion, five hundred fifty million, eight hundred three thousand, five hundred nineteen".
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