1183802993983 has 2 divisors, whose sum is σ = 1183802993984. Its totient is φ = 1183802993982.

The previous prime is 1183802993941. The next prime is 1183802994047. The reversal of 1183802993983 is 3893992083811.

It is an a-pointer prime, because the next prime (1183802994047) can be obtained adding 1183802993983 to its sum of digits (64).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1183802993983 - 2¹³ = 1183802985791 is a prime.

It is a super-2 number, since 2×1183802993983² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1183802993083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 591901496991 + 591901496992.

It is an arithmetic number, because the mean of its divisors is an integer number (591901496992).

Almost surely, 2^{1183802993983} is an apocalyptic number.

1183802993983 is a deficient number, since it is larger than the sum of its proper divisors (1).

1183802993983 is an equidigital number, since it uses as much as digits as its factorization.

1183802993983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20155392, while the sum is 64.

The spelling of 1183802993983 in words is "one trillion, one hundred eighty-three billion, eight hundred two million, nine hundred ninety-three thousand, nine hundred eighty-three".