Base | Representation |
---|---|
bin | 110111101110111000… |
… | …1101010110100001101 |
3 | 102102221001020222111222 |
4 | 1233131301222310031 |
5 | 3430103313332112 |
6 | 130552114453125 |
7 | 11434621611542 |
oct | 1573561526415 |
9 | 372831228458 |
10 | 119684902157 |
11 | 46838009487 |
12 | 1b2422941a5 |
13 | b394b31542 |
14 | 5b15562bc9 |
15 | 31a74b3372 |
hex | 1bddc6ad0d |
119684902157 has 2 divisors, whose sum is σ = 119684902158. Its totient is φ = 119684902156.
The previous prime is 119684902151. The next prime is 119684902189. The reversal of 119684902157 is 751209486911.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 73143743401 + 46541158756 = 270451^2 + 215734^2 .
It is a cyclic number.
It is not a de Polignac number, because 119684902157 - 220 = 119683853581 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 119684902099 and 119684902108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (119684902151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59842451078 + 59842451079.
It is an arithmetic number, because the mean of its divisors is an integer number (59842451079).
Almost surely, 2119684902157 is an apocalyptic number.
It is an amenable number.
119684902157 is a deficient number, since it is larger than the sum of its proper divisors (1).
119684902157 is an equidigital number, since it uses as much as digits as its factorization.
119684902157 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1088640, while the sum is 53.
The spelling of 119684902157 in words is "one hundred nineteen billion, six hundred eighty-four million, nine hundred two thousand, one hundred fifty-seven".
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