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119688115901 is a prime number
BaseRepresentation
bin110111101110111110…
…1111011011010111101
3102102221021022020221112
41233131331323122331
53430110124202101
6130552311411405
711434661125214
oct1573575733275
9372837266845
10119688115901
1146839903a72
121b243383b65
13b3956b8273
145b15b5c07b
1531a78ea6bb
hex1bddf7b6bd

119688115901 has 2 divisors, whose sum is σ = 119688115902. Its totient is φ = 119688115900.

The previous prime is 119688115819. The next prime is 119688115903. The reversal of 119688115901 is 109511886911.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 75125328100 + 44562787801 = 274090^2 + 211099^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-119688115901 is a prime.

It is a super-3 number, since 3×1196881159013 (a number of 34 digits) contains 333 as substring.

Together with 119688115903, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 119688115901.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (119688115903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59844057950 + 59844057951.

It is an arithmetic number, because the mean of its divisors is an integer number (59844057951).

Almost surely, 2119688115901 is an apocalyptic number.

It is an amenable number.

119688115901 is a deficient number, since it is larger than the sum of its proper divisors (1).

119688115901 is an equidigital number, since it uses as much as digits as its factorization.

119688115901 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 155520, while the sum is 50.

The spelling of 119688115901 in words is "one hundred nineteen billion, six hundred eighty-eight million, one hundred fifteen thousand, nine hundred one".