119760101999 has 2 divisors, whose sum is σ = 119760102000. Its totient is φ = 119760101998.

The previous prime is 119760101969. The next prime is 119760102001. The reversal of 119760101999 is 999101067911.

It is a strong prime.

It is an emirp because it is prime and its reverse (999101067911) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-119760101999 is a prime.

Together with 119760102001, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 119760101999.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (119760101939) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59880050999 + 59880051000.

It is an arithmetic number, because the mean of its divisors is an integer number (59880051000).

Almost surely, 2^119760101999 is an apocalyptic number.

119760101999 is a deficient number, since it is larger than the sum of its proper divisors (1).

119760101999 is an equidigital number, since it uses as much as digits as its factorization.

119760101999 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 275562, while the sum is 53.

The spelling of 119760101999 in words is "one hundred nineteen billion, seven hundred sixty million, one hundred one thousand, nine hundred ninety-nine".