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119838084029 is a prime number
BaseRepresentation
bin110111110011011101…
…0000000101110111101
3102110022201111102112122
41233212322000232331
53430412022142104
6131015230012325
711441461623116
oct1574672005675
9373281442478
10119838084029
1146906524274
121b2856470a5
13b3ba7a57c1
145b2ba3920d
1531b5b706be
hex1be6e80bbd

119838084029 has 2 divisors, whose sum is σ = 119838084030. Its totient is φ = 119838084028.

The previous prime is 119838083987. The next prime is 119838084031. The reversal of 119838084029 is 920480838911.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 81470284900 + 38367799129 = 285430^2 + 195877^2 .

It is an emirp because it is prime and its reverse (920480838911) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 119838084029 - 216 = 119838018493 is a prime.

It is a super-2 number, since 2×1198380840292 (a number of 23 digits) contains 22 as substring.

Together with 119838084031, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (119838084049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59919042014 + 59919042015.

It is an arithmetic number, because the mean of its divisors is an integer number (59919042015).

Almost surely, 2119838084029 is an apocalyptic number.

It is an amenable number.

119838084029 is a deficient number, since it is larger than the sum of its proper divisors (1).

119838084029 is an equidigital number, since it uses as much as digits as its factorization.

119838084029 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 995328, while the sum is 53.

The spelling of 119838084029 in words is "one hundred nineteen billion, eight hundred thirty-eight million, eighty-four thousand, twenty-nine".