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12000131244223 is a prime number
BaseRepresentation
bin1010111010011111111110…
…0011110110000010111111
31120111012102210001000000121
42232213333203312002333
53033102232044303343
641304441215035411
72345660303404513
oct256477743660277
946435383030017
1012000131244223
113907255276601
12141985780bb67
136907b89527a5
142d6b491c4143
1515c23e6e7aed
hexae9ff8f60bf

12000131244223 has 2 divisors, whose sum is σ = 12000131244224. Its totient is φ = 12000131244222.

The previous prime is 12000131244217. The next prime is 12000131244229. The reversal of 12000131244223 is 32244213100021.

It is a balanced prime because it is at equal distance from previous prime (12000131244217) and next prime (12000131244229).

It is a cyclic number.

It is not a de Polignac number, because 12000131244223 - 213 = 12000131236031 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12000131244229) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000065622111 + 6000065622112.

It is an arithmetic number, because the mean of its divisors is an integer number (6000065622112).

Almost surely, 212000131244223 is an apocalyptic number.

12000131244223 is a deficient number, since it is larger than the sum of its proper divisors (1).

12000131244223 is an equidigital number, since it uses as much as digits as its factorization.

12000131244223 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 12000131244223 its reverse (32244213100021), we get a palindrome (44244344344244).

The spelling of 12000131244223 in words is "twelve trillion, one hundred thirty-one million, two hundred forty-four thousand, two hundred twenty-three".