12000141443232 has 72 divisors (see below), whose sum is σ = 34129026087156. Its totient is φ = 3999622373376.

The previous prime is 12000141443221. The next prime is 12000141443233. The reversal of 12000141443232 is 23234414100021.

12000141443232 is a `hidden beast` number, since 1 + 200 + 0 + 1 + 414 + 43 + 2 + 3 + 2 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 11999323712016 + 817731216 = 3464004^2 + 28596^2 .

It is a tau number, because it is divible by the number of its divisors (72).

It is a junction number, because it is equal to n+sod(n) for n = 12000141443196 and 12000141443205.

It is not an unprimeable number, because it can be changed into a prime (12000141443233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 510208 + ... + 4925504.

Almost surely, 2^{12000141443232} is an apocalyptic number.

12000141443232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

12000141443232 is an abundant number, since it is smaller than the sum of its proper divisors (22128884643924).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12000141443232 is a wasteful number, since it uses less digits than its factorization.

12000141443232 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4424750 (or 4424739 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 27.

Adding to 12000141443232 its reverse (23234414100021), we get a palindrome (35234555543253).

The spelling of 12000141443232 in words is "twelve trillion, one hundred forty-one million, four hundred forty-three thousand, two hundred thirty-two".