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12000230300957 is a prime number
BaseRepresentation
bin1010111010100000010101…
…1101101101110100011101
31120111012200200102121022112
42232220011131231310131
53033102432424112312
641304455114123405
72345662615360613
oct256500535556435
946435620377275
1012000230300957
1139072a6183378
121419884a20565
13690803325b42
142d6b5840b6b3
1515c248262d22
hexaea0576dd1d

12000230300957 has 2 divisors, whose sum is σ = 12000230300958. Its totient is φ = 12000230300956.

The previous prime is 12000230300921. The next prime is 12000230300959. The reversal of 12000230300957 is 75900303200021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11446353496516 + 553876804441 = 3383246^2 + 744229^2 .

It is a cyclic number.

It is not a de Polignac number, because 12000230300957 - 220 = 12000229252381 is a prime.

Together with 12000230300959, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12000230300959) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000115150478 + 6000115150479.

It is an arithmetic number, because the mean of its divisors is an integer number (6000115150479).

Almost surely, 212000230300957 is an apocalyptic number.

It is an amenable number.

12000230300957 is a deficient number, since it is larger than the sum of its proper divisors (1).

12000230300957 is an equidigital number, since it uses as much as digits as its factorization.

12000230300957 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11340, while the sum is 32.

Adding to 12000230300957 its reverse (75900303200021), we get a palindrome (87900533500978).

The spelling of 12000230300957 in words is "twelve trillion, two hundred thirty million, three hundred thousand, nine hundred fifty-seven".