Search a number
-
+
1200220121300 = 225212002201213
BaseRepresentation
bin10001011101110010101…
…100011010100011010100
311020201222101220102122012
4101131302230122203110
5124131022322340200
62315212402323352
7152466400463054
oct21356254324324
94221871812565
101200220121300
11423012a72522
1217473b359558
13892460986b5
144213b867564
15213491bba35
hex11772b1a8d4

1200220121300 has 18 divisors (see below), whose sum is σ = 2604477663438. Its totient is φ = 480088048480.

The previous prime is 1200220121291. The next prime is 1200220121323. The reversal of 1200220121300 is 31210220021.

It is a happy number.

It can be written as a sum of positive squares in 3 ways, for example, as 72380369296 + 1127839752004 = 269036^2 + 1061998^2 .

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 6001100507 + ... + 6001100706.

Almost surely, 21200220121300 is an apocalyptic number.

1200220121300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1200220121300 is an abundant number, since it is smaller than the sum of its proper divisors (1404257542138).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1200220121300 is a wasteful number, since it uses less digits than its factorization.

1200220121300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12002201227 (or 12002201220 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 1200220121300 its reverse (31210220021), we get a palindrome (1231430341321).

The spelling of 1200220121300 in words is "one trillion, two hundred billion, two hundred twenty million, one hundred twenty-one thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 12002201213 24004402426 48008804852 60011006065 120022012130 240044024260 300055030325 600110060650 1200220121300