Base | Representation |
---|---|
bin | 11011010010101011101011… |
… | …110110111100001110000010 |
3 | 120201222212021122120101111100 |
4 | 123102223223312330032002 |
5 | 111213042204423232320 |
6 | 1103141310534355230 |
7 | 34165650610166022 |
oct | 3322535366741602 |
9 | 521885248511440 |
10 | 120031113102210 |
11 | 35277a00161422 |
12 | 11566a00abbb16 |
13 | 51c8b682ac31b |
14 | 218d773267a82 |
15 | dd2440d52790 |
hex | 6d2aebdbc382 |
120031113102210 has 48 divisors (see below), whose sum is σ = 317196974310840. Its totient is φ = 31483570648320.
The previous prime is 120031113102179. The next prime is 120031113102223. The reversal of 120031113102210 is 12201311130021.
120031113102210 is a `hidden beast` number, since 1 + 2 + 0 + 0 + 311 + 131 + 0 + 221 + 0 = 666.
It can be written as a sum of positive squares in 4 ways, for example, as 38081129922081 + 81949983180129 = 6170991^2 + 9052623^2 .
It is a super-3 number, since 3×1200311131022103 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 10931789875 + ... + 10931800854.
Almost surely, 2120031113102210 is an apocalyptic number.
120031113102210 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
120031113102210 is an abundant number, since it is smaller than the sum of its proper divisors (197165861208630).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
120031113102210 is a wasteful number, since it uses less digits than its factorization.
120031113102210 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21863590803 (or 21863590800 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 18.
Adding to 120031113102210 its reverse (12201311130021), we get a palindrome (132232424232231).
The spelling of 120031113102210 in words is "one hundred twenty trillion, thirty-one billion, one hundred thirteen million, one hundred two thousand, two hundred ten".
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