12011201301101 has 2 divisors, whose sum is σ = 12011201301102. Its totient is φ = 12011201301100.

The previous prime is 12011201301049. The next prime is 12011201301103. The reversal of 12011201301101 is 10110310211021.

12011201301101 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6774953059876 + 5236248241225 = 2602874^2 + 2288285^2 .

It is a cyclic number.

It is not a de Polignac number, because 12011201301101 - 2⁶ = 12011201301037 is a prime.

Together with 12011201301103, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12011201301103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005600650550 + 6005600650551.

It is an arithmetic number, because the mean of its divisors is an integer number (6005600650551).

Almost surely, 2^{12011201301101} is an apocalyptic number.

It is an amenable number.

12011201301101 is a deficient number, since it is larger than the sum of its proper divisors (1).

12011201301101 is an equidigital number, since it uses as much as digits as its factorization.

12011201301101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 12011201301101 its reverse (10110310211021), we get a palindrome (22121511512122).

The spelling of 12011201301101 in words is "twelve trillion, eleven billion, two hundred one million, three hundred one thousand, one hundred one".