12012133001039 has 2 divisors, whose sum is σ = 12012133001040. Its totient is φ = 12012133001038.

The previous prime is 12012133000957. The next prime is 12012133001041. The reversal of 12012133001039 is 93010033121021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12012133001039 - 2²⁰ = 12012131952463 is a prime.

Together with 12012133001041, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12012133000999 and 12012133001017.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12012133001059) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006066500519 + 6006066500520.

It is an arithmetic number, because the mean of its divisors is an integer number (6006066500520).

Almost surely, 2^{12012133001039} is an apocalyptic number.

12012133001039 is a deficient number, since it is larger than the sum of its proper divisors (1).

12012133001039 is an equidigital number, since it uses as much as digits as its factorization.

12012133001039 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 26.

The spelling of 12012133001039 in words is "twelve trillion, twelve billion, one hundred thirty-three million, one thousand, thirty-nine".