Base | Representation |
---|---|
bin | 100011110011001… |
… | …0001001101011100 |
3 | 10002201022000020112 |
4 | 1013212101031130 |
5 | 4430002324200 |
6 | 315110105152 |
7 | 41524103336 |
oct | 10746211534 |
9 | 3081260215 |
10 | 1201214300 |
11 | 5670660a0 |
12 | 29634b1b8 |
13 | 161b2b0c0 |
14 | b5768456 |
15 | 706ca535 |
hex | 4799135c |
1201214300 has 144 divisors (see below), whose sum is σ = 3086802432. Its totient is φ = 399993600.
The previous prime is 1201214291. The next prime is 1201214303. The reversal of 1201214300 is 34121021.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1201214303) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2387849 + ... + 2388351.
It is an arithmetic number, because the mean of its divisors is an integer number (21436128).
Almost surely, 21201214300 is an apocalyptic number.
1201214300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1201214300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1543401216).
1201214300 is an abundant number, since it is smaller than the sum of its proper divisors (1885588132).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1201214300 is a wasteful number, since it uses less digits than its factorization.
1201214300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 708 (or 701 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 14.
The square root of 1201214300 is about 34658.5386304732. The cubic root of 1201214300 is about 1063.0168889856.
Adding to 1201214300 its reverse (34121021), we get a palindrome (1235335321).
It can be divided in two parts, 120121 and 4300, that added together give a palindrome (124421).
The spelling of 1201214300 in words is "one billion, two hundred one million, two hundred fourteen thousand, three hundred".
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