Base | Representation |
---|---|
bin | 11011010100000000010101… |
… | …001001110001111111010000 |
3 | 120202022112212201201100121021 |
4 | 123110000111021301333100 |
5 | 111221034324024020422 |
6 | 1103251141325005224 |
7 | 34205346101016112 |
oct | 3324002511617720 |
9 | 522275781640537 |
10 | 120122000220112 |
11 | 353024aa606300 |
12 | 115805469b3814 |
13 | 52045c0b37627 |
14 | 2193d15ccb3b2 |
15 | dd49b0013dc7 |
hex | 6d4015271fd0 |
120122000220112 has 120 divisors (see below), whose sum is σ = 268431479910720. Its totient is φ = 51935182464000.
The previous prime is 120122000220107. The next prime is 120122000220113. The reversal of 120122000220112 is 211022000221021.
It is a happy number.
It is a Harshad number since it is a multiple of its sum of digits (16).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120122000220113) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 435112 + ... + 15505912.
It is an arithmetic number, because the mean of its divisors is an integer number (2236928999256).
Almost surely, 2120122000220112 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 120122000220112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (134215739955360).
120122000220112 is an abundant number, since it is smaller than the sum of its proper divisors (148309479690608).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
120122000220112 is a wasteful number, since it uses less digits than its factorization.
120122000220112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15071033 (or 15071016 counting only the distinct ones).
The product of its (nonzero) digits is 64, while the sum is 16.
Adding to 120122000220112 its reverse (211022000221021), we get a palindrome (331144000441133).
Subtracting 120122000220112 from its reverse (211022000221021), we obtain a palindrome (90900000000909).
The spelling of 120122000220112 in words is "one hundred twenty trillion, one hundred twenty-two billion, two hundred twenty thousand, one hundred twelve".
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