Base | Representation |
---|---|
bin | 10001011110101110010… |
… | …111001110110011010011 |
3 | 11020211120011121112222002 |
4 | 101132232113032303103 |
5 | 124140100111413412 |
6 | 2315500003104215 |
7 | 152533244512064 |
oct | 21365627166323 |
9 | 4224504545862 |
10 | 1201221201107 |
11 | 423487063604 |
12 | 17497a67206b |
13 | 893755c3205 |
14 | 421d47b656b |
15 | 213a7012dc2 |
hex | 117ae5cecd3 |
1201221201107 has 2 divisors, whose sum is σ = 1201221201108. Its totient is φ = 1201221201106.
The previous prime is 1201221201097. The next prime is 1201221201109. The reversal of 1201221201107 is 7011021221021.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1201221201107 - 218 = 1201220938963 is a prime.
Together with 1201221201109, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1201221201109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600610600553 + 600610600554.
It is an arithmetic number, because the mean of its divisors is an integer number (600610600554).
Almost surely, 21201221201107 is an apocalyptic number.
1201221201107 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201221201107 is an equidigital number, since it uses as much as digits as its factorization.
1201221201107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 20.
Adding to 1201221201107 its reverse (7011021221021), we get a palindrome (8212242422128).
The spelling of 1201221201107 in words is "one trillion, two hundred one billion, two hundred twenty-one million, two hundred one thousand, one hundred seven".
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