Base | Representation |
---|---|
bin | 1010111011010000000100… |
… | …0010101010011000100111 |
3 | 1120112102202111000122110101 |
4 | 2232310001002222120213 |
5 | 3033310201444031043 |
6 | 41314414224004531 |
7 | 2346625232500405 |
oct | 256640102523047 |
9 | 46472674018411 |
10 | 12013041002023 |
11 | 391177a514726 |
12 | 142025b160747 |
13 | 691a95419229 |
14 | 2d761197c475 |
15 | 15c747c7124d |
hex | aed010aa627 |
12013041002023 has 2 divisors, whose sum is σ = 12013041002024. Its totient is φ = 12013041002022.
The previous prime is 12013041002021. The next prime is 12013041002069. The reversal of 12013041002023 is 32020014031021.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12013041002023 - 21 = 12013041002021 is a prime.
Together with 12013041002021, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12013041002021) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006520501011 + 6006520501012.
It is an arithmetic number, because the mean of its divisors is an integer number (6006520501012).
Almost surely, 212013041002023 is an apocalyptic number.
12013041002023 is a deficient number, since it is larger than the sum of its proper divisors (1).
12013041002023 is an equidigital number, since it uses as much as digits as its factorization.
12013041002023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288, while the sum is 19.
Adding to 12013041002023 its reverse (32020014031021), we get a palindrome (44033055033044).
The spelling of 12013041002023 in words is "twelve trillion, thirteen billion, forty-one million, two thousand, twenty-three".
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