1201312230037 has 2 divisors, whose sum is σ = 1201312230038. Its totient is φ = 1201312230036.

The previous prime is 1201312229977. The next prime is 1201312230047. The reversal of 1201312230037 is 7300322131021.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 639158676676 + 562153553361 = 799474^2 + 749769^2 .

It is a cyclic number.

It is not a de Polignac number, because 1201312230037 - 2¹⁹ = 1201311705749 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1201312229993 and 1201312230020.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1201312230047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600656115018 + 600656115019.

It is an arithmetic number, because the mean of its divisors is an integer number (600656115019).

Almost surely, 2^{1201312230037} is an apocalyptic number.

It is an amenable number.

1201312230037 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201312230037 is an equidigital number, since it uses as much as digits as its factorization.

1201312230037 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512, while the sum is 25.

Adding to 1201312230037 its reverse (7300322131021), we get a palindrome (8501634361058).

The spelling of 1201312230037 in words is "one trillion, two hundred one billion, three hundred twelve million, two hundred thirty thousand, thirty-seven".