Base | Representation |
---|---|
bin | 1010111011010000011001… |
… | …0110001101100110110110 |
3 | 1120112102222200111212201022 |
4 | 2232310012112031212312 |
5 | 3033310342240404420 |
6 | 41314431123501142 |
7 | 2346630363204062 |
oct | 256640626154666 |
9 | 46472880455638 |
10 | 12013130013110 |
11 | 3911815790006 |
12 | 1420284b277b2 |
13 | 691aaa9b3005 |
14 | 2d761d70caa2 |
15 | 15c7509a4c25 |
hex | aed0658d9b6 |
12013130013110 has 64 divisors (see below), whose sum is σ = 23756799744000. Its totient is φ = 4353418726272.
The previous prime is 12013130013107. The next prime is 12013130013151. The reversal of 12013130013110 is 1131003131021.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 18902291 + ... + 19527489.
It is an arithmetic number, because the mean of its divisors is an integer number (371199996000).
Almost surely, 212013130013110 is an apocalyptic number.
12013130013110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12013130013110 is a deficient number, since it is larger than the sum of its proper divisors (11743669730890).
12013130013110 is a wasteful number, since it uses less digits than its factorization.
12013130013110 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 629645.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 12013130013110 its reverse (1131003131021), we get a palindrome (13144133144131).
The spelling of 12013130013110 in words is "twelve trillion, thirteen billion, one hundred thirty million, thirteen thousand, one hundred ten".
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