Base | Representation |
---|---|
bin | 1010111011010000011001… |
… | …1101110011011110011110 |
3 | 1120112102222211020222122110 |
4 | 2232310012131303132132 |
5 | 3033310343243100410 |
6 | 41314431234254450 |
7 | 2346630416133141 |
oct | 256640635633636 |
9 | 46472884228573 |
10 | 12013132003230 |
11 | 391181691a236 |
12 | 1420285727426 |
13 | 691aab22bab7 |
14 | 2d761daaa058 |
15 | 15c750c49720 |
hex | aed0677379e |
12013132003230 has 32 divisors (see below), whose sum is σ = 28832616582048. Its totient is φ = 3203379670400.
The previous prime is 12013132003183. The next prime is 12013132003253. The reversal of 12013132003230 is 3230023131021.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 12013132003197 and 12013132003206.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6836361 + ... + 8412020.
It is an arithmetic number, because the mean of its divisors is an integer number (901019268189).
Almost surely, 212013132003230 is an apocalyptic number.
12013132003230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12013132003230 is an abundant number, since it is smaller than the sum of its proper divisors (16819484578818).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12013132003230 is a wasteful number, since it uses less digits than its factorization.
12013132003230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15274652.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 12013132003230 its reverse (3230023131021), we get a palindrome (15243155134251).
The spelling of 12013132003230 in words is "twelve trillion, thirteen billion, one hundred thirty-two million, three thousand, two hundred thirty".
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