120132000020310 has 32 divisors (see below), whose sum is σ = 288338428553472. Its totient is φ = 32032796838240.

The previous prime is 120132000020297. The next prime is 120132000020323. The reversal of 120132000020310 is 13020000231021.

It is an interprime number because it is at equal distance from previous prime (120132000020297) and next prime (120132000020323).

It is a super-3 number, since 3×120132000020310³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 120132000020310.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 149791354 + ... + 150591213.

It is an arithmetic number, because the mean of its divisors is an integer number (9010575892296).

Almost surely, 2^{120132000020310} is an apocalyptic number.

120132000020310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

120132000020310 is an abundant number, since it is smaller than the sum of its proper divisors (168206428533162).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120132000020310 is a wasteful number, since it uses less digits than its factorization.

120132000020310 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 300395908.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 120132000020310 its reverse (13020000231021), we get a palindrome (133152000251331).

The spelling of 120132000020310 in words is "one hundred twenty trillion, one hundred thirty-two billion, twenty thousand, three hundred ten".