Base | Representation |
---|---|
bin | 11011010100001001111100… |
… | …010100110100010100011111 |
3 | 120202100112112000021102200012 |
4 | 123110021330110310110133 |
5 | 111221221443200213322 |
6 | 1103300005413153435 |
7 | 34206162623036111 |
oct | 3324117424642437 |
9 | 522315460242605 |
10 | 120132321101087 |
11 | 353069164669a9 |
12 | 1158254732b87b |
13 | 5205577153ca9 |
14 | 21946148db3b1 |
15 | dd4db6157ae2 |
hex | 6d427c53451f |
120132321101087 has 2 divisors, whose sum is σ = 120132321101088. Its totient is φ = 120132321101086.
The previous prime is 120132321101083. The next prime is 120132321101119. The reversal of 120132321101087 is 780101123231021.
It is an a-pointer prime, because the next prime (120132321101119) can be obtained adding 120132321101087 to its sum of digits (32).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120132321101087 - 22 = 120132321101083 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120132321101083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60066160550543 + 60066160550544.
It is an arithmetic number, because the mean of its divisors is an integer number (60066160550544).
Almost surely, 2120132321101087 is an apocalyptic number.
120132321101087 is a deficient number, since it is larger than the sum of its proper divisors (1).
120132321101087 is an equidigital number, since it uses as much as digits as its factorization.
120132321101087 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 32.
The spelling of 120132321101087 in words is "one hundred twenty trillion, one hundred thirty-two billion, three hundred twenty-one million, one hundred one thousand, eighty-seven".
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