Base | Representation |
---|---|
bin | 10110011000000110… |
… | …01110011010011111 |
3 | 1011000020012111120221 |
4 | 23030003032122133 |
5 | 144100403112002 |
6 | 5304023222211 |
7 | 603462431626 |
oct | 131403163237 |
9 | 34006174527 |
10 | 12013332127 |
11 | 5105238265 |
12 | 23b32a7967 |
13 | 1195b51c64 |
14 | 81d6cc6bd |
15 | 4a4a05c37 |
hex | 2cc0ce69f |
12013332127 has 2 divisors, whose sum is σ = 12013332128. Its totient is φ = 12013332126.
The previous prime is 12013332109. The next prime is 12013332137. The reversal of 12013332127 is 72123331021.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12013332127 - 27 = 12013331999 is a prime.
It is a super-3 number, since 3×120133321273 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12013332137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006666063 + 6006666064.
It is an arithmetic number, because the mean of its divisors is an integer number (6006666064).
Almost surely, 212013332127 is an apocalyptic number.
12013332127 is a deficient number, since it is larger than the sum of its proper divisors (1).
12013332127 is an equidigital number, since it uses as much as digits as its factorization.
12013332127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 12013332127 its reverse (72123331021), we get a palindrome (84136663148).
The spelling of 12013332127 in words is "twelve billion, thirteen million, three hundred thirty-two thousand, one hundred twenty-seven".
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