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12013332132 = 22317532394649
BaseRepresentation
bin10110011000000110…
…01110011010100100
31011000020012111121010
423030003032122210
5144100403112012
65304023222220
7603462431634
oct131403163244
934006174533
1012013332132
11510523826a
1223b32a7970
131195b51c69
1481d6cc6c4
154a4a05c3c
hex2cc0ce6a4

12013332132 has 96 divisors (see below), whose sum is σ = 30373056000. Its totient is φ = 3681513472.

The previous prime is 12013332127. The next prime is 12013332137. The reversal of 12013332132 is 23123331021.

It is an interprime number because it is at equal distance from previous prime (12013332127) and next prime (12013332137).

It is a junction number, because it is equal to n+sod(n) for n = 12013332099 and 12013332108.

It is not an unprimeable number, because it can be changed into a prime (12013332137) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2581744 + ... + 2586392.

It is an arithmetic number, because the mean of its divisors is an integer number (316386000).

Almost surely, 212013332132 is an apocalyptic number.

12013332132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12013332132, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15186528000).

12013332132 is an abundant number, since it is smaller than the sum of its proper divisors (18359723868).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12013332132 is a wasteful number, since it uses less digits than its factorization.

12013332132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4965 (or 4963 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 12013332132 its reverse (23123331021), we get a palindrome (35136663153).

It can be divided in two parts, 1201 and 3332132, that added together give a palindrome (3333333).

The spelling of 12013332132 in words is "twelve billion, thirteen million, three hundred thirty-two thousand, one hundred thirty-two".

Divisors: 1 2 3 4 6 12 17 34 51 53 68 102 106 159 204 212 239 318 478 636 717 901 956 1434 1802 2703 2868 3604 4063 4649 5406 8126 9298 10812 12189 12667 13947 16252 18596 24378 25334 27894 38001 48756 50668 55788 76002 79033 152004 158066 215339 237099 246397 316132 430678 474198 492794 646017 739191 861356 948396 985588 1111111 1292034 1478382 2222222 2584068 2956764 3333333 4188749 4444444 6666666 8377498 12566247 13333332 16754996 18888887 25132494 37777774 50264988 56666661 58888883 75555548 113333322 117777766 176666649 226666644 235555532 353333298 706666596 1001111011 2002222022 3003333033 4004444044 6006666066 12013332132