12013434439 has 4 divisors (see below), whose sum is σ = 12014245080. Its totient is φ = 12012623800.

The previous prime is 12013434431. The next prime is 12013434449. The reversal of 12013434439 is 93443431021.

12013434439 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12013434439 - 2³ = 12013434431 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12013434431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 382669 + ... + 412870.

It is an arithmetic number, because the mean of its divisors is an integer number (3003561270).

Almost surely, 2^12013434439 is an apocalyptic number.

12013434439 is a deficient number, since it is larger than the sum of its proper divisors (810641).

12013434439 is an equidigital number, since it uses as much as digits as its factorization.

12013434439 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 810640.

The product of its (nonzero) digits is 31104, while the sum is 34.

The spelling of 12013434439 in words is "twelve billion, thirteen million, four hundred thirty-four thousand, four hundred thirty-nine".