12013434438 has 16 divisors (see below), whose sum is σ = 25440214320. Its totient is φ = 3768920576.

The previous prime is 12013434431. The next prime is 12013434449. The reversal of 12013434438 is 83443431021.

It is a super-2 number, since 2×12013434438² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12013434399 and 12013434408.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12013434431) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 58889283 + ... + 58889486.

It is an arithmetic number, because the mean of its divisors is an integer number (1590013395).

Almost surely, 2^12013434438 is an apocalyptic number.

12013434438 is an abundant number, since it is smaller than the sum of its proper divisors (13426779882).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12013434438 is a wasteful number, since it uses less digits than its factorization.

12013434438 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 117778791.

The product of its (nonzero) digits is 27648, while the sum is 33.

Adding to 12013434438 its reverse (83443431021), we get a palindrome (95456865459).

The spelling of 12013434438 in words is "twelve billion, thirteen million, four hundred thirty-four thousand, four hundred thirty-eight".