12014114202373 has 2 divisors, whose sum is σ = 12014114202374. Its totient is φ = 12014114202372.

The previous prime is 12014114202283. The next prime is 12014114202449. The reversal of 12014114202373 is 37320241141021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8685032973444 + 3329081228929 = 2947038^2 + 1824577^2 .

It is a cyclic number.

It is not a de Polignac number, because 12014114202373 - 2²⁵ = 12014080647941 is a prime.

It is a super-2 number, since 2×12014114202373² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12014114202773) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6007057101186 + 6007057101187.

It is an arithmetic number, because the mean of its divisors is an integer number (6007057101187).

Almost surely, 2^{12014114202373} is an apocalyptic number.

It is an amenable number.

12014114202373 is a deficient number, since it is larger than the sum of its proper divisors (1).

12014114202373 is an equidigital number, since it uses as much as digits as its factorization.

12014114202373 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8064, while the sum is 31.

Adding to 12014114202373 its reverse (37320241141021), we get a palindrome (49334355343394).

The spelling of 12014114202373 in words is "twelve trillion, fourteen billion, one hundred fourteen million, two hundred two thousand, three hundred seventy-three".