Base | Representation |
---|---|
bin | 10001011111100011010… |
… | …110100100011101010101 |
3 | 11020220212010110101210002 |
4 | 101133203112210131111 |
5 | 124143410204020432 |
6 | 2320124121541045 |
7 | 152564261164202 |
oct | 21374326443525 |
9 | 4226763411702 |
10 | 1202110220117 |
11 | 4238a2975764 |
12 | 174b88344785 |
13 | 89487843671 |
14 | 4227a8b4ca9 |
15 | 2140a0c0e62 |
hex | 117e35a4755 |
1202110220117 has 2 divisors, whose sum is σ = 1202110220118. Its totient is φ = 1202110220116.
The previous prime is 1202110220093. The next prime is 1202110220231. The reversal of 1202110220117 is 7110220112021.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 975420917956 + 226689302161 = 987634^2 + 476119^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1202110220117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1202110270117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601055110058 + 601055110059.
It is an arithmetic number, because the mean of its divisors is an integer number (601055110059).
Almost surely, 21202110220117 is an apocalyptic number.
It is an amenable number.
1202110220117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1202110220117 is an equidigital number, since it uses as much as digits as its factorization.
1202110220117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 20.
Adding to 1202110220117 its reverse (7110220112021), we get a palindrome (8312330332138).
The spelling of 1202110220117 in words is "one trillion, two hundred two billion, one hundred ten million, two hundred twenty thousand, one hundred seventeen".
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