Base | Representation |
---|---|
bin | 110111111110100100… |
… | …1110101010000101101 |
3 | 102111021201211021212221 |
4 | 1233331021311100231 |
5 | 3432143100030333 |
6 | 131120241555341 |
7 | 11453643306061 |
oct | 1577511652055 |
9 | 374251737787 |
10 | 120211330093 |
11 | 46a88186598 |
12 | 1b36a645b51 |
13 | b449c0a76a |
14 | 5b65437aa1 |
15 | 31d87ebd2d |
hex | 1bfd27542d |
120211330093 has 2 divisors, whose sum is σ = 120211330094. Its totient is φ = 120211330092.
The previous prime is 120211330081. The next prime is 120211330139. The reversal of 120211330093 is 390033112021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 114164245924 + 6047084169 = 337882^2 + 77763^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120211330093 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120211330003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60105665046 + 60105665047.
It is an arithmetic number, because the mean of its divisors is an integer number (60105665047).
Almost surely, 2120211330093 is an apocalyptic number.
It is an amenable number.
120211330093 is a deficient number, since it is larger than the sum of its proper divisors (1).
120211330093 is an equidigital number, since it uses as much as digits as its factorization.
120211330093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 25.
The spelling of 120211330093 in words is "one hundred twenty billion, two hundred eleven million, three hundred thirty thousand, ninety-three".
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