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12021222000121 is a prime number
BaseRepresentation
bin1010111011101110100010…
…1010101100010111111001
31120120012212122000102001221
42232323220222230113321
53033423430313000441
641322250111112041
72350335042023665
oct256735052542771
946505778012057
1012021222000121
113915198476684
121421962b12621
1369279a2c25c9
142d7b8a2bd8a5
1515ca760c08d1
hexaeee8aac5f9

12021222000121 has 2 divisors, whose sum is σ = 12021222000122. Its totient is φ = 12021222000120.

The previous prime is 12021222000119. The next prime is 12021222000143. The reversal of 12021222000121 is 12100022212021.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10484229540096 + 1536992460025 = 3237936^2 + 1239755^2 .

It is a cyclic number.

It is not a de Polignac number, because 12021222000121 - 21 = 12021222000119 is a prime.

Together with 12021222000119, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 12021222000095 and 12021222000104.

It is not a weakly prime, because it can be changed into another prime (12021222003121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6010611000060 + 6010611000061.

It is an arithmetic number, because the mean of its divisors is an integer number (6010611000061).

Almost surely, 212021222000121 is an apocalyptic number.

It is an amenable number.

12021222000121 is a deficient number, since it is larger than the sum of its proper divisors (1).

12021222000121 is an equidigital number, since it uses as much as digits as its factorization.

12021222000121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64, while the sum is 16.

Adding to 12021222000121 its reverse (12100022212021), we get a palindrome (24121244212142).

The spelling of 12021222000121 in words is "twelve trillion, twenty-one billion, two hundred twenty-two million, one hundred twenty-one", and thus it is an aban number.