1202140232471 has 2 divisors, whose sum is σ = 1202140232472. Its totient is φ = 1202140232470.

The previous prime is 1202140232437. The next prime is 1202140232473. The reversal of 1202140232471 is 1742320412021.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1202140232471 is a prime.

It is a super-3 number, since 3×1202140232471³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 1202140232473, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1202140232473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601070116235 + 601070116236.

It is an arithmetic number, because the mean of its divisors is an integer number (601070116236).

Almost surely, 2^{1202140232471} is an apocalyptic number.

1202140232471 is a deficient number, since it is larger than the sum of its proper divisors (1).

1202140232471 is an equidigital number, since it uses as much as digits as its factorization.

1202140232471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5376, while the sum is 29.

Adding to 1202140232471 its reverse (1742320412021), we get a palindrome (2944460644492).

The spelling of 1202140232471 in words is "one trillion, two hundred two billion, one hundred forty million, two hundred thirty-two thousand, four hundred seventy-one".