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12022121093 is a prime number
BaseRepresentation
bin10110011001001001…
…10000001010000101
31011000211202000210012
423030210300022011
5144110130333333
65304535440005
7603630225503
oct131444601205
934024660705
1012022121093
11510a1a0574
1223b6226005
13119790b528
14820939673
154a568ee48
hex2cc930285

12022121093 has 2 divisors, whose sum is σ = 12022121094. Its totient is φ = 12022121092.

The previous prime is 12022121087. The next prime is 12022121099. The reversal of 12022121093 is 39012122021.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (12022121087) and next prime (12022121099).

It can be written as a sum of positive squares in only one way, i.e., 7280696929 + 4741424164 = 85327^2 + 68858^2 .

It is an emirp because it is prime and its reverse (39012122021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12022121093 - 28 = 12022120837 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12022121099) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6011060546 + 6011060547.

It is an arithmetic number, because the mean of its divisors is an integer number (6011060547).

Almost surely, 212022121093 is an apocalyptic number.

It is an amenable number.

12022121093 is a deficient number, since it is larger than the sum of its proper divisors (1).

12022121093 is an equidigital number, since it uses as much as digits as its factorization.

12022121093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 23.

The spelling of 12022121093 in words is "twelve billion, twenty-two million, one hundred twenty-one thousand, ninety-three".