Base | Representation |
---|---|
bin | 11011010101011100101110… |
… | …101001000100010111100110 |
3 | 120202200000221222101001101210 |
4 | 123111130232221010113212 |
5 | 111224201020244200240 |
6 | 1103404510135532250 |
7 | 34215460465050414 |
oct | 3325345651042746 |
9 | 522600858331353 |
10 | 120221212100070 |
11 | 35340591085124 |
12 | 1159781482a086 |
13 | 5210a72293643 |
14 | 2198a483d62b4 |
15 | dd7369e71780 |
hex | 6d572ea445e6 |
120221212100070 has 32 divisors (see below), whose sum is σ = 289653597420768. Its totient is φ = 31934246739968.
The previous prime is 120221212099981. The next prime is 120221212100071. The reversal of 120221212100070 is 70001212122021.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120221212100071) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7796439249 + ... + 7796454668.
It is an arithmetic number, because the mean of its divisors is an integer number (9051674919399).
Almost surely, 2120221212100070 is an apocalyptic number.
120221212100070 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
120221212100070 is an abundant number, since it is smaller than the sum of its proper divisors (169432385320698).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
120221212100070 is a wasteful number, since it uses less digits than its factorization.
120221212100070 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15592894184.
The product of its (nonzero) digits is 224, while the sum is 21.
Adding to 120221212100070 its reverse (70001212122021), we get a palindrome (190222424222091).
The spelling of 120221212100070 in words is "one hundred twenty trillion, two hundred twenty-one billion, two hundred twelve million, one hundred thousand, seventy".
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