1202214443711 has 2 divisors, whose sum is σ = 1202214443712. Its totient is φ = 1202214443710.

The previous prime is 1202214443701. The next prime is 1202214443743. The reversal of 1202214443711 is 1173444122021.

It is an a-pointer prime, because the next prime (1202214443743) can be obtained adding 1202214443711 to its sum of digits (32).

It is a weak prime.

It is an emirp because it is prime and its reverse (1173444122021) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1202214443711 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1202214443701) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601107221855 + 601107221856.

It is an arithmetic number, because the mean of its divisors is an integer number (601107221856).

Almost surely, 2^{1202214443711} is an apocalyptic number.

1202214443711 is a deficient number, since it is larger than the sum of its proper divisors (1).

1202214443711 is an equidigital number, since it uses as much as digits as its factorization.

1202214443711 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10752, while the sum is 32.

Adding to 1202214443711 its reverse (1173444122021), we get a palindrome (2375658565732).

The spelling of 1202214443711 in words is "one trillion, two hundred two billion, two hundred fourteen million, four hundred forty-three thousand, seven hundred eleven".