Base | Representation |
---|---|
bin | 10110011001100010… |
… | …11000110100000110 |
3 | 1011001001222022100101 |
4 | 23030301120310012 |
5 | 144112002331400 |
6 | 5305134434314 |
7 | 604000332310 |
oct | 131461306406 |
9 | 34031868311 |
10 | 12025433350 |
11 | 5111053077 |
12 | 23b736299a |
13 | 11984cb048 |
14 | 82115c7b0 |
15 | 4a5ae656a |
hex | 2ccc58d06 |
12025433350 has 24 divisors (see below), whose sum is σ = 25562636208. Its totient is φ = 4123005600.
The previous prime is 12025433347. The next prime is 12025433353. The reversal of 12025433350 is 5333452021.
It is an interprime number because it is at equal distance from previous prime (12025433347) and next prime (12025433353).
It is a super-2 number, since 2×120254333502 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12025433353) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 17178841 + ... + 17179540.
It is an arithmetic number, because the mean of its divisors is an integer number (1065109842).
Almost surely, 212025433350 is an apocalyptic number.
12025433350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12025433350 is an abundant number, since it is smaller than the sum of its proper divisors (13537202858).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12025433350 is a wasteful number, since it uses less digits than its factorization.
12025433350 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 34358400 (or 34358395 counting only the distinct ones).
The product of its (nonzero) digits is 10800, while the sum is 28.
Adding to 12025433350 its reverse (5333452021), we get a palindrome (17358885371).
The spelling of 12025433350 in words is "twelve billion, twenty-five million, four hundred thirty-three thousand, three hundred fifty".
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