Base | Representation |
---|---|
bin | 11011010111000011111010… |
… | …111001000000011000011101 |
3 | 120210001121221212211121002112 |
4 | 123113003322321000120131 |
5 | 111233004430312400014 |
6 | 1103531432540003405 |
7 | 34226462313214514 |
oct | 3327037271003035 |
9 | 523047855747075 |
10 | 120332013012509 |
11 | 3538357a329641 |
12 | 115b5197830565 |
13 | 521b34c6a281c |
14 | 21a0159b0167b |
15 | dda1a252173e |
hex | 6d70fae4061d |
120332013012509 has 2 divisors, whose sum is σ = 120332013012510. Its totient is φ = 120332013012508.
The previous prime is 120332013012439. The next prime is 120332013012511. The reversal of 120332013012509 is 905210310233021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 118952222136484 + 1379790876025 = 10906522^2 + 1174645^2 .
It is a cyclic number.
It is not a de Polignac number, because 120332013012509 - 216 = 120332012946973 is a prime.
Together with 120332013012511, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120332013012529) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60166006506254 + 60166006506255.
It is an arithmetic number, because the mean of its divisors is an integer number (60166006506255).
Almost surely, 2120332013012509 is an apocalyptic number.
It is an amenable number.
120332013012509 is a deficient number, since it is larger than the sum of its proper divisors (1).
120332013012509 is an equidigital number, since it uses as much as digits as its factorization.
120332013012509 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9720, while the sum is 32.
The spelling of 120332013012509 in words is "one hundred twenty trillion, three hundred thirty-two billion, thirteen million, twelve thousand, five hundred nine".
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