Base | Representation |
---|---|
bin | 1010111100011011001111… |
… | …1110111000010000110111 |
3 | 1120121100212000000102120021 |
4 | 2233012303332320100313 |
5 | 3034123020042014033 |
6 | 41331553014150011 |
7 | 2351241324610111 |
oct | 257066376702067 |
9 | 46540760012507 |
10 | 12033223001143 |
11 | 391a296751343 |
12 | 1424152052307 |
13 | 693960717946 |
14 | 2d85a80bc3b1 |
15 | 15d02998cb2d |
hex | af1b3fb8437 |
12033223001143 has 2 divisors, whose sum is σ = 12033223001144. Its totient is φ = 12033223001142.
The previous prime is 12033223001141. The next prime is 12033223001213. The reversal of 12033223001143 is 34110032233021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12033223001143 - 21 = 12033223001141 is a prime.
Together with 12033223001141, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12033223001141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6016611500571 + 6016611500572.
It is an arithmetic number, because the mean of its divisors is an integer number (6016611500572).
Almost surely, 212033223001143 is an apocalyptic number.
12033223001143 is a deficient number, since it is larger than the sum of its proper divisors (1).
12033223001143 is an equidigital number, since it uses as much as digits as its factorization.
12033223001143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 12033223001143 its reverse (34110032233021), we get a palindrome (46143255234164).
The spelling of 12033223001143 in words is "twelve trillion, thirty-three billion, two hundred twenty-three million, one thousand, one hundred forty-three".
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