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120791309141 is a prime number
BaseRepresentation
bin111000001111110111…
…0010001101101010101
3102112210011011021120102
41300133232101231111
53434340033343031
6131254000543445
711504215121066
oct1603756215525
9375704137512
10120791309141
11472555aa418
121b4b0921b85
13b510116529
145bbc48c56d
15321e6b27cb
hex1c1fb91b55

120791309141 has 2 divisors, whose sum is σ = 120791309142. Its totient is φ = 120791309140.

The previous prime is 120791309033. The next prime is 120791309143. The reversal of 120791309141 is 141903197021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 120568672900 + 222636241 = 347230^2 + 14921^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120791309141 is a prime.

Together with 120791309143, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 120791309095 and 120791309104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120791309143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60395654570 + 60395654571.

It is an arithmetic number, because the mean of its divisors is an integer number (60395654571).

Almost surely, 2120791309141 is an apocalyptic number.

It is an amenable number.

120791309141 is a deficient number, since it is larger than the sum of its proper divisors (1).

120791309141 is an equidigital number, since it uses as much as digits as its factorization.

120791309141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13608, while the sum is 38.

The spelling of 120791309141 in words is "one hundred twenty billion, seven hundred ninety-one million, three hundred nine thousand, one hundred forty-one".