Base | Representation |
---|---|
bin | 1010111111111010000011… |
… | …0101011111011011001111 |
3 | 1120211002020010220120120022 |
4 | 2233332200311133123033 |
5 | 3041113012004041101 |
6 | 41415243434012355 |
7 | 2355456406105403 |
oct | 257764065373317 |
9 | 46732203816508 |
10 | 12093031315151 |
11 | 3942697a04926 |
12 | 14338638770bb |
13 | 6994a253bb67 |
14 | 2db43d315103 |
15 | 15e87a479a1b |
hex | affa0d5f6cf |
12093031315151 has 2 divisors, whose sum is σ = 12093031315152. Its totient is φ = 12093031315150.
The previous prime is 12093031315147. The next prime is 12093031315153. The reversal of 12093031315151 is 15151313039021.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12093031315151 - 22 = 12093031315147 is a prime.
Together with 12093031315153, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12093031315153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6046515657575 + 6046515657576.
It is an arithmetic number, because the mean of its divisors is an integer number (6046515657576).
Almost surely, 212093031315151 is an apocalyptic number.
12093031315151 is a deficient number, since it is larger than the sum of its proper divisors (1).
12093031315151 is an equidigital number, since it uses as much as digits as its factorization.
12093031315151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12150, while the sum is 35.
The spelling of 12093031315151 in words is "twelve trillion, ninety-three billion, thirty-one million, three hundred fifteen thousand, one hundred fifty-one".
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