Base | Representation |
---|---|
bin | 10110100010011100… |
… | …10000011011100101 |
3 | 1011020021111021112012 |
4 | 23101032100123211 |
5 | 144240112010203 |
6 | 5320403204005 |
7 | 605565144533 |
oct | 132116203345 |
9 | 34207437465 |
10 | 12100110053 |
11 | 514a218859 |
12 | 2418376605 |
13 | 11aab16445 |
14 | 82b03b153 |
15 | 4ac447bd8 |
hex | 2d13906e5 |
12100110053 has 2 divisors, whose sum is σ = 12100110054. Its totient is φ = 12100110052.
The previous prime is 12100110031. The next prime is 12100110067. The reversal of 12100110053 is 35001100121.
It is an a-pointer prime, because the next prime (12100110067) can be obtained adding 12100110053 to its sum of digits (14).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7053144289 + 5046965764 = 83983^2 + 71042^2 .
It is a cyclic number.
It is not a de Polignac number, because 12100110053 - 28 = 12100109797 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12100110073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050055026 + 6050055027.
It is an arithmetic number, because the mean of its divisors is an integer number (6050055027).
Almost surely, 212100110053 is an apocalyptic number.
It is an amenable number.
12100110053 is a deficient number, since it is larger than the sum of its proper divisors (1).
12100110053 is an equidigital number, since it uses as much as digits as its factorization.
12100110053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30, while the sum is 14.
Adding to 12100110053 its reverse (35001100121), we get a palindrome (47101210174).
The spelling of 12100110053 in words is "twelve billion, one hundred million, one hundred ten thousand, fifty-three".
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