Base | Representation |
---|---|
bin | 11011100000110011010001… |
… | …011110001111110001110000 |
3 | 120212102121120221112101210222 |
4 | 123200303101132033301300 |
5 | 111324441212223430000 |
6 | 1105203124530512212 |
7 | 34326025555412063 |
oct | 3340632136176160 |
9 | 525377527471728 |
10 | 121001333030000 |
11 | 35611416aa7295 |
12 | 116a2a51735668 |
13 | 52694b8926657 |
14 | 21c46d25548da |
15 | dec7c7e33a85 |
hex | 6e0cd178fc70 |
121001333030000 has 50 divisors (see below), whose sum is σ = 292956327423144. Its totient is φ = 48400533208000.
The previous prime is 121001333029991. The next prime is 121001333030003. The reversal of 121001333030000 is 30333100121.
It is a tau number, because it is divible by the number of its divisors (50).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (121001333030003) by changing a digit.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 6050056652 + ... + 6050076651.
Almost surely, 2121001333030000 is an apocalyptic number.
121001333030000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
121001333030000 is an abundant number, since it is smaller than the sum of its proper divisors (171954994393144).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121001333030000 is an equidigital number, since it uses as much as digits as its factorization.
121001333030000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12100133331 (or 12100133310 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 121001333030000 its reverse (30333100121), we get a palindrome (121031666130121).
The spelling of 121001333030000 in words is "one hundred twenty-one trillion, one billion, three hundred thirty-three million, thirty thousand".
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