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12100536654653 is a prime number
BaseRepresentation
bin1011000000010110000000…
…1100000101101100111101
31120211210121012112022211102
42300011200030011230331
53041223344340422103
641422524303302445
72356143402330566
oct260054014055475
946753535468742
1012100536654653
113945899532547
1214351b92aaa25
1369a0ca449355
142db95201716d
1515eb69313e88
hexb0160305b3d

12100536654653 has 2 divisors, whose sum is σ = 12100536654654. Its totient is φ = 12100536654652.

The previous prime is 12100536654629. The next prime is 12100536654677. The reversal of 12100536654653 is 35645663500121.

It is a balanced prime because it is at equal distance from previous prime (12100536654629) and next prime (12100536654677).

It can be written as a sum of positive squares in only one way, i.e., 11856542148889 + 243994505764 = 3443333^2 + 493958^2 .

It is a cyclic number.

It is not a de Polignac number, because 12100536654653 - 28 = 12100536654397 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12100536654598 and 12100536654607.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12100536654683) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050268327326 + 6050268327327.

It is an arithmetic number, because the mean of its divisors is an integer number (6050268327327).

Almost surely, 212100536654653 is an apocalyptic number.

It is an amenable number.

12100536654653 is a deficient number, since it is larger than the sum of its proper divisors (1).

12100536654653 is an equidigital number, since it uses as much as digits as its factorization.

12100536654653 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944000, while the sum is 47.

The spelling of 12100536654653 in words is "twelve trillion, one hundred billion, five hundred thirty-six million, six hundred fifty-four thousand, six hundred fifty-three".