Base | Representation |
---|---|
bin | 1011000000010111110010… |
… | …0101111110000101011111 |
3 | 1120211211211102020101212021 |
4 | 2300011330211332011133 |
5 | 3041230333334414442 |
6 | 41423043445321011 |
7 | 2356161250033345 |
oct | 260057445760537 |
9 | 46754742211767 |
10 | 12101013201247 |
11 | 3946013530003 |
12 | 1435310a06167 |
13 | 69a1750ac199 |
14 | 2db999425995 |
15 | 15eb96097e67 |
hex | b017c97e15f |
12101013201247 has 2 divisors, whose sum is σ = 12101013201248. Its totient is φ = 12101013201246.
The previous prime is 12101013201209. The next prime is 12101013201307. The reversal of 12101013201247 is 74210231010121.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12101013201247 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12101013271247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050506600623 + 6050506600624.
It is an arithmetic number, because the mean of its divisors is an integer number (6050506600624).
Almost surely, 212101013201247 is an apocalyptic number.
12101013201247 is a deficient number, since it is larger than the sum of its proper divisors (1).
12101013201247 is an equidigital number, since it uses as much as digits as its factorization.
12101013201247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 672, while the sum is 25.
Adding to 12101013201247 its reverse (74210231010121), we get a palindrome (86311244211368).
The spelling of 12101013201247 in words is "twelve trillion, one hundred one billion, thirteen million, two hundred one thousand, two hundred forty-seven".
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