12103012121 has 2 divisors, whose sum is σ = 12103012122. Its totient is φ = 12103012120.

The previous prime is 12103012111. The next prime is 12103012123. The reversal of 12103012121 is 12121030121.

12103012121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7886328025 + 4216684096 = 88805^2 + 64936^2 .

It is a cyclic number.

It is not a de Polignac number, because 12103012121 - 2¹⁰ = 12103011097 is a prime.

Together with 12103012123, it forms a pair of twin primes.

It is a Chen prime.

It is an alternating number because its digits alternate between odd and even.

It is a junction number, because it is equal to n+sod(n) for n = 12103012096 and 12103012105.

It is not a weakly prime, because it can be changed into another prime (12103012123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6051506060 + 6051506061.

It is an arithmetic number, because the mean of its divisors is an integer number (6051506061).

Almost surely, 2^12103012121 is an apocalyptic number.

It is an amenable number.

12103012121 is a deficient number, since it is larger than the sum of its proper divisors (1).

12103012121 is an equidigital number, since it uses as much as digits as its factorization.

12103012121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 12103012121 its reverse (12121030121), we get a palindrome (24224042242).

The spelling of 12103012121 in words is "twelve billion, one hundred three million, twelve thousand, one hundred twenty-one".